Una avioneta vuela entre las ciudades A y B. Su altura viene dada por la siguiente funcion: h(t)=840t-30t elevado al 2,, siendo h(T) la altura de la avioneta( en metros) a los t (minutos) de haber despegado. a) cuanto dura la avioneta para ir desde la ciudad A hasta la ciudad B?
b) a que altura la avioneta inicia el descenso?
c) grafique la funcion e indique su dominio e imagen

linearly: 8560 bacteria

exponentially: approximately 75233 bacteria

step-by-step explanation:

assuming it is not exponential (we would have some really complicated logarithms), let's say it is linear. then, after 5 hours, it increased by 1200 bacteria, so every hour it increases by 240 bacteria. this means that after 19 hours, we get 19 * 240 + 4000 bacteria or 3800 + 760 + 4000 = 7800 + 760 = 8560 bacteria.

because it says round your answer, i will do this exponentially (with a calculator, of course). first, we need to find how much it multiplies by every hour, by taking the 5th root of 52/40 or 13/10. this is approximately 0.167. we still need to add 1 to this, because we are multiplying by that number, not adding that amount of the number. now, we just calculate 4000 * (1.167)^19. use a calculator to get approximately 75232.6, or 75233.

the answer is ! ?

hmu if ur willing to do a algebra a online class i’ll pay 600 hmu on the gram profitpreme