An aircraft carrier made a trip to a navigational buoy and back. On the trip there it traveled 24 kilometers per hour and on the return trip it went 22 kilometers per hour. If the round trip took
12 hours, how long did it take to travel to the navigational buoy?

Thanx for the points noob

Step-by-step explanation:

14

step-by-step explanation:

14 x 3 = 42

p ÷ r = tan(x)

step-by-step explanation:

given that there is a figure below shows a right triangle: a right triangle is shown with hypotenuse equal to q units and the length of the legs equal to p units and r units.

graph is missing so i will create the graph as per given information.

the angle between the legs having lengths p units and q units is y degrees. the angle between the legs having lengths r units and q units is x degrees.

now we need to find about what is p ÷ r equal to.

so we can use trigonometric ratio tan(x)=[altitude]/[base] to find the value of p ÷ r, because p is the altitude and r is the base.

p ÷ r=tan(x)

hence final answer is p ÷ r=tan(x).