A research group is on a college campus and is conducting a survey regarding the coffee consumption of college students in America. They randomly select three sample groups of 100 registered students to complete their survey, which asks the students to identify the average number of 8-ounce cups of coffee they consume each day. The results of the three sample groups are shown in the table below. 0 1 2 3 4+
Sample #1 38 19 26 16 1
Sample #2 32 14 37 15 2
Sample #3 41 22 31 6 0
Given the results of this survey, if there are 12,000 registered students, which of the following ranges is the best estimate for the number of registered students that do not drink coffee?

4,500-6,000
4,500-5,000
3,500-6,000
3,800-5,000

total = principal × ( 1 + rate ) ^ years

total = 600 * (1.04)^5

total = 729.99

answer is c

step-by-step explanation:

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step-by-step explanation:

answer: the correct answer is -32

step-by-step explanation:

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.