The height of a basketball thrown by a 6 foot tall man follows a path defined by the function h(x) = -0.5x^2 + 3x + 6 h(x) = −0.5x^2 + 3x + 6, where x is the horizontal distance from where it is thrown. How far away from the basket should the player stand in order for the ball to go in the basket (10 feet high) on its way down? Show all work.

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step-by-step explanation:

127

whether it's diameter, or radius, i believe if i remember correctly from school, every amount has to always add up to 180. so if you take 53, and starting adding, long story short, taking 127 and adding it to 53, gives you 180.

step-by-step explanation:

for volume, add base x height x width

-1

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