Mathematics, 28.04.2021 19:30 pedropaulofpedrosapp
The work of a student to solve a set of equations is shown: Equation 1: m = 8 + 2n Equation 2: 3m = 4 + 4n Step 1:β3(m) = β3(8 + 2n) [Equation 1 is multiplied by β3.] 3m = 4 + 4n [Equation 2] Step 2:β3m = β24 β 6n [Equation 1 in Step 1 is simplified.] 3m = 4 + 4n [Equation 2] Step 3: β3m + 3m = β24 β 6n + 4n [Equations in Step 2 are added.] Step 4:0 = β24 β 2n Step 5:n = β12 In which step did the student first make an error?
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The work of a student to solve a set of equations is shown: Equation 1: m = 8 + 2n Equation 2: 3m =...
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