Practice Tools Assessment Name
Reasoning
Miranda mixed 34.5 fluid ounces of blue paint, 40.5 fluid
ounces of red paint, and 2 fluid ounces of black paint to
make purple paint. She poured the same amount of the
purple paint into each of 14 jars. How much paint did
she pour in each jar?
1. Explain what each of the quantities in the problem
means.
Sue made chicken soup by combining the entire can of soup shown
with a full can of water. How many 10-fluid ounce bowls can she fill
with the soup? How much soup will be left over?

the photograph is photographer and- in the process- ourselves.

step-by-step explanation:

the answer would be  

a.

3: 1

step-by-step explanation:

hello!

to begin with, we're given that on earth, a rock weighs 20 pounds, and while on jupiter, that same rock weighs 42 pounds. now, we're trying to find the weight of a rock that weighs 10.5 pounds on earth, on jupiter.

to solve this, first, set up a proportion, cross-multiply, and solve it algebraically.

setting up the proportion is the hardest and the most confusing part of the problem, but it's simple.

if on earth, the rock weighs 20 lbs, and on jupiter it weighs 42 lbs, our first part of our proportion is 20/42 lbs. the second part has to be equal to each other. this means that 10.5 has to be on the numerator of the fraction, and x, the value we're trying to find, has to be on the denominator. remember that the rock weighs 10.5 lbs on earth, and we're trying to find the weight of it on jupiter (which is x).

20/42 = 10.5/x

next, you would cross-multiply.

20x = 42(10.5)

20x = 441

now, solve it algebraically by using division.

x = 22.05 lbs

this can be rounded to 22.1 lbs.

therefore, the weight of the rock on jupiter is 22.1 lbs, the fourth choice.