The function f is continuous on the closed interval [_2,1] with f(-2)=7 and f(1)=-2. Of the following conditions, which could guarantee that there is a number c in the open interval (-2,1) where f’(c) =-3? A) f is never increasing on the closed interval [-2,1].
B) f is differential on the open interval (-2,1).
C) f has both a minimum and maximum on the closed interval [-2,1].
D);f(0)=1

idn

step-by-step explanation:

step-by-step explanation:

use pothagarean therom

a^2+b^2=c^2 so first ac

acm is a right triangle because c= 90°

and am (the hypotenuse or c) =16+9 =25

but there is not enough info we need another angle or side length

in the attachment.   i didn't see your choices.   the word which means there is choices.

step-by-step explanation:

(x,y)

x tells you how much left or right you go from the origin

y tells you how much down or up you go from the origin

so for example (-3,2), you go left 3 and up twice. i denoted which of the ordered pairs is which in my graph.