The perimeters of two squares in the model are given. Find the perimeter of the third square. P=12 units p=16 units ​

20 units

Step-by-step explanation:

1) find the side of the first square

side = P / 4 = 12:4 = 3 units

2) find the side of the second square

side = P / 4 = 16 : 4 = 4 units

3) use the Pythagorean theorem to find the hypotenuse of the right triangle

units

4)  find the perimeter of the third square

P = side x 4 = 5 x 4 = 20 units

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3