A rectangular pyramid has a height of 10 meters. The base measures 8 meters in length and 12 meters in width. Two different triangular cross sections are formed through the vertex and perpendicular to the base. What is the difference in the areas of the cross sections? Enter your answer in the box. m2
PLZ HELP

The answer is  30 m²

Step-by-step explanation:

step 1

find the area of the first cross section

area1=b1*h/2

b1=8 m

h=10 m

area1=6*10/2> 30 m²

step 2

find the area of the second cross section

area 2=b2*h/2

b2=12 m

h=10 m

area1=12*10/2> 60 m²

step 3

find the difference in the areas of the cross sections

difference=60-30> 30 m²

area1=b1*h/2

b1=8 m

h=10 m

area1=6*10/2> 30 m²

area 2=b2*h/2

b2=12 m

h=10 m

area1=12*10/2> 60 m²

difference=60-30> 30 m²

30 m²

Step-by-step explanation: hope this helps

well there are two answers for that.

1: you need 120 ones then that will equal up to 120.

2: you could also do one 100 and 2 tens.

those are the answers that i have thought of.

beluga wheeeaaalle matt

step-by-step explanation: