An economist studying fuel costs suspected that the mean price of gasoline in her state was more than \$3$3dollar sign, 3 per gallon on a certain day. On that day, she sampled 404040 gas stations to test H_0: \mu=\$3H 0 ​ :μ=$3H, start subscript, 0, end subscript, colon, mu, equals, dollar sign, 3 versus H_\text{a}: \mu>\$3H a ​ :μ>$3H, start subscript, start text, a, end text, end subscript, colon, mu, is greater than, dollar sign, 3, where \muμmu is the mean price of gasoline per gallon that day in her state. The sample data had a mean of \bar x=\$3.04 x ˉ =$3.04x, with, \bar, on top, equals, dollar sign, 3, point, 04 and a standard deviation of s_x=\$0.39s x ​ =$0.39s, start subscript, x, end subscript, equals, dollar sign, 0, point, 39. These results produced a test statistic of t\approx0.65t≈0.65t, approximately equals, 0, point, 65 and a P-value of approximately 0.2600.2600, point, 260.

answer: haha (: i’ll go see what it is

step-by-step explanation:

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .

dont know

step-by-step explanation:

-3.5 is the distance.

i've had this question so choose the one in the absolute value sign.