D. How many milliliters (mL) of water must be added to 10 milliliters of a 30%-sulfuric acid solution to make a 15%-sulfuric acid solution?

a)(x-2)^2+(y-1)^2=9

step-by-step explanation:

(picture explains)

twenty-six miles over two gallons because the proportion for the original 13 miles to one gallon would be written 13/1 and, doing the same thing to the top and bottom, i multiplied by 2 and got 26/2

step-by-step explanation:

*calories burned = (weight)(calorie factor)*

calories burned = 180 (0.65)

calories burned = 117

the calories he used up is 117, which is 65% of his weight.