Solve for a

2a+3b=12-2(2b+a)

PLEASE SHOW WORK ILL MARK BRAINLIEST.

a = 3 - (7/4)b

Step-by-step explanation:

Start by performing the indicated multiplication:

2a+3b=12-2(2b+a)  =>  2a+3b=12 - 4b - 2a

Next, combine like terms:  4a + 7b = 12

Isolate 4a by subtracting 7b from both sides:  

4a = 12 - 7b

Finally, divide both sides by 4:

a = 3 - (7/4)b

5x + 3y = - 4

step-by-step explanation:

the equation of a line in standard form is

ax + by = c ( a is a positive integer and b, c are integers )

express the line first of all in slope- intercept form

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / ( x₂ - x₁ )

with (x₁, y₁ ) = (7, - 3) and (x₂, y₂ ) = (4, - 8)

m = = -

y = - x + c ← is the partial equation

to find c substitute either of the 2 points into the partial equation

using (4, - 8 ), then

- 8 = - + c ⇒ c = -

y = - x - ← in slope-intercept form

multiply all terms by 3 to eliminate the fractions

3y = - 5x - 4 ( add 5x to both sides )

5x + 3y = - 4 ← in standard form

faster, im not sure why but i know it is faster