A cylindrical bucket having inner height and radius 32cm and 8cm respectively, is filled with sand. This bucket is emptied on a level ground and a conical heap of sand is formed. If the height of the conical heap is 24cm, find the radius and slant height of the heap.​

As we know if a solid object turn into another or if a thing which take a shape of one object turn into another object then there volume will be equal.

Take pie = ¶

volume of cylinder = volume of cone

¶×rsquare×h= 1/3¶r square h

18×18×32×3/24=r square

18×18×8×3/6= r square

18×18×4×3/3=r square

√18×18×2×2=r

18×2=r

r =36 cm

h= 24 cm

slant height = √36×36+24×24

slant height = √1872

slant height=

√2×2×2×2×13×3×3

slant height = 12√13 cm

Step-by-step explanation:

you ignore the remainder, therefore the answer is y = x+2

step-by-step explanation:

you have to divide the denominator by the numerator. you can use synthetic division or long division.

[-5] .     1 .     7 .     11

x + 2 + 1/x+5