The vertex of f(x) = 3x ^2+ 5x + 2 is a:
minimum
maximum
none of these

minimum

Step-by-step explanation:

Given a quadratic in standard form f(x) = ax² + bx + c ( a ≠ 0 )

• If a > 0 then vertex is a minimum

• If a < 0 then vertex is a maximum

f(x) = 3x² + 5x + 2 ← is in standard form

with a = 3

Since a > 0 then vertex is a minimum

i dont know if you cant find a way its best to actually add all of them start from 105 tho

step-by-step explanation:

y < -3

step-by-step explanation:

-3y - 2 > 7

-3y -2 + 2 > 7+2

-3y > 9

-3y/-3 < 9/-3   (change the inequality sign when multiplying or dividing by a negative number)

y < -3