Write the equations of 2 straight lines which are perpendicular to y = -3x +0.5.

there is another person who already asked and answered this question i think

y = (1/3)x + 7

y = (1/3)x - 15

These are two examples out of an unlimited number of possibilities.

Step-by-step explanation:

The slope of this given line is -3.  Any new line perpendicular to this one is the negative reciprocal of -3:  1/3.

The slope-intercept form is y = mx + b.  Here m = 1/3, so the revised form is

y = (1/3)x + b.

Two straight lines perpendicular to the given line are easily found by selecting two different values for b:

y = (1/3)x + 7

y = (1/3)x - 15

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step-by-step explanation: