In a sequence of numbers, a4=9, a5=13, a6=17, a7=21, and a8=25. Which equation can be used to find the nth term of the sequence, an?

A = an=4n+9

B = an=7n−4

C = an=4n−7

D = an=9n+4

The first one, i believe, would be correct. all the others have one thing in common, and that's that they have repeating numbers. in the second one, x and y have repeating 6's and 3's, and in the third, x and y have repeating 6's as well. in the last one, there are repeating 3's. the first one has no repeating numbers.

Im not that good with division but i think 5 is -6but dont quote me on thatim not the best in division but thats my answer

D.