Mathematics, 24.04.2021 03:10 ccamiloggonzales1234
As bridge building, craftily clever Calpurnia does dazzlingly double-duty dinners, emcee-ing elegant, elegiac, eleemosynary events: for forty-four favorite uffy fat-cats, Georgia'sgolden girl gladly helps heavy hitters initiate inimitable joviality. In Calpurnia's experi-ence the population of all her donations is approximatelyNormally distributed. TonightCalpurnia's 44 fat-cats donate $27,500, with Standard Deviations s= $125.
Required:
a. Estimate the mean donation for Calpurnia's population of fat-cats.
b. To draw any inferences from these data, what must we assume about the population of fat-cat donations, and why? We shall assume this for the remainder of this problem.
c. For Calpurnia's sample of 45 donors, suppose that s = $120.
i. Find a 90% confidence interval for Calpurnia's population mean donation.
ii. Find a 98% confidence interval for Calpurnia's population mean donation.
iii. Compare your answers in c. i. and c. ii.: which interval is wider, and why?
d. Calpurnia believes she can rake in more than $400 per party-goer, on average. What hypotheses should she use to test this? Define in words any parameters.
e. To test these hypotheses, what test-statistic should Calpurnia use?
Answers: 2
Mathematics, 21.06.2019 21:00
When solving this problem: 3025/5.5 = a/90.75 you get 49912.5 which would be the length of one of the sides of a square when the area is only 90.75 inches. is that answer correct, why, and how is it possible?
Answers: 1
Mathematics, 21.06.2019 21:20
The radius of the circle below intersects the unit circle at (3/5,4/5). what is the approximate value of theta? 0.6 radians 1.0 radians 36.9 degrees 53.1 degrees
Answers: 3
Mathematics, 21.06.2019 22:00
Percent increase and decrease. original number: 45 new number: 18
Answers: 1
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