Find the volume of this regular hexagonal pyramid

83 is the volume according to my best knowledge and remembrance of Geometry. I hope these calculations help!

Step-by-step explanation:

Since a right triangle is established upon the indication of the right angle marking, and the 50 degree marking is apparent around the one of the legs, the resulting angle of the right triangle unidentified is 40 degrees. Now, the formula is 1/3 × (the area of the base) × (the height), where finding the base area dictates that we apply Area = (3√3 s^2)/ 2, where s = side length, (3√3 (4)^2)/ 2 = 24√3, Substitution Property of Equality: 1/3 * 24√3 * x; find x, "the radius of a hexagon is equal to the length of one side" (mathblog), use the cosine ratio because cosine = adjacent over hypotenuse, cos(50) = 4 (according to the length of side equal radius of hexagon)/x = 6, 1/3 * 24√3 * 6 = 48√3 = 83 is the volume.

it would to have a graph or something ! but i had this question so its false

step-by-step explanation:

4 + 5 7/9= 9 7/9

step-by-step explanation: