​​In the figure shown, \overset{\leftrightarrow }{CF} CF
↔
intersects \overset{\leftrightarrow }{AD}
AD
↔
and \overset{\leftrightarrow }{EH}
EH
↔
at points BB and FF, respectively.

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​Part A

​Given: \angle CBD\cong \angle BFE∠CBD≅∠BFE
​​Prove: \angle ABF\cong \angle BFE∠ABF≅∠BFE
​Select from the drop-down menus to support each line of the proof.
​

​​Statement: \angle CBD\cong \angle BFE∠CBD≅∠BFE Reason:

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​Statement : \angle CBD\cong \angle ABF∠CBD≅∠ABF Reason:

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​Statement: \angle ABF\cong \angle BFE∠ABF≅∠BFE Reason:

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​Part B

Given: m\angle CBD=m\angle BFEm∠CBD=m∠BFE
Prove: m\angle BFE+m\angle DBF=180^{\circ}m∠BFE+m∠DBF=180
∘

Select from the drop-down menus to support each line of the proof.
​

​Statement: m\angle CBD=m\angle BFEm∠CBD=m∠BFE Reason:

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​Statement: m\angle CBD+m\angle DBF=180^{\circ}m∠CBD+m∠DBF=180
∘
Reason:

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​Statement: m\angle BFE+m\angle DBF=180^{\circ}m∠BFE+m∠DBF=180
∘
Reason:

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