What is the overlap of Data Set 1 and Data Set 2? High moderate low none Two line plots with the same scale and interval, from fifty two to sixty two, with tick marks every one unit. The plots are stacked vertically for comparison. Each plot has eleven data values. Values appear as x marks above the line. Upper plot data values are one x mark above fifty three, one x mark above fifty four, one x mark above fifty five, two x marks above fifty six, three x marks above fifty seven, two x marks above fifty eight, and one x mark above sixty. Lower plot data values are one x mark above fifty four, one x mark above fifty five, two x marks above fifty six, three x marks above fifty seven, two x marks above fifty eight, one x mark above fifty nine and one x mark above sixty.

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

the two may have that, even a breakdown is probably offered

step-by-step explanation:

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the answer would be 1 1/72

step-by-step explanation:

you can rewrite the equation by separating the parts and then solving individually:

10-9=1

1/8 - 1/9=

find l c d and then combine:

1 1/72