subject
Mathematics, 22.04.2021 23:30 karyme12

Change the quadratic equation y= x^2+4x-5 from standard form to vertex form. 1. Transpose the -value to the left side of the equation.

2. Complete the square of the expression on the right side of the equation to get a perfect square trinomial. Add the resulting term to both sides.

3. Add the numbers on the left and factor the trinomial on the right.

4. Transpose the number across to the right side to get the equation into the vertex form, .

5. Make sure the addition and subtraction signs are correct to give the proper vertex form.

a. y= (x---2)^2

b. Y+9=(x+2)^2

c. y= (x---2)^2---9

d. y= a (x-h)^2 + k
Y= [x - (-2)]^2+ (-9)

e. Y=(x+2)^2-9

f. Y+5 = x^2+4x

g. Y+5+_4_=x^2+4x+_4_

ansver
Answers: 2

Another question on Mathematics

question
Mathematics, 21.06.2019 15:30
Which of the following are parts of a sphere
Answers: 1
question
Mathematics, 21.06.2019 16:30
In the figure shown below, m < 40 and ab =8. which equation could be used to find x?
Answers: 2
question
Mathematics, 21.06.2019 18:30
Which expression is not a polynomial?
Answers: 2
question
Mathematics, 21.06.2019 18:30
What is coefficient of the term of degree of degree 5 in the polynomial below
Answers: 1
You know the right answer?
Change the quadratic equation y= x^2+4x-5 from standard form to vertex form. 1. Transpose the -val...
Questions
question
Mathematics, 31.08.2021 01:20
question
English, 31.08.2021 01:20
question
Mathematics, 31.08.2021 01:20
Questions on the website: 13722367