HELP A quarter circle is attached to the side of a square as shown. What is the best approximation for the area of this figure?

Use 3.14 to approximate pi.

28.56 m²

Step-by-step explanation:

What we need to do for the quarter circle is use the following formula: 1/4(πr²)

(4 * 4) + 1/4(3.14 * 4²)

16 + 1/4(3.14 * 16)

16 + 1/4(50.24)

16 + 12.56

28.56 m²

The best approximation for the area of this figure is 28.56 m².

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°