Y=x+2
3x+3y=6
solving systems by substitution

6

Step-by-step explanation:Reorder

2

2

and

−

x

-

x

.

y

=

−

x

+

2

y

=

-

x

+

2

3

x

+

3

y

=

6

3

x

+

3

y

=

6

Replace all occurrences of

y

y

in

3

x

+

3

y

=

6

3

x

+

3

y

=

6

with

−

x

+

2

-

x

+

2

.

y

=

−

x

+

2

y

=

-

x

+

2

3

x

+

3

(

−

x

+

2

)

=

6

3

x

+

3

(

-

x

+

2

)

=

6

Simplify

3

x

+

3

(

−

x

+

2

)

3

x

+

3

(

-

x

+

2

)

.

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y

=

−

x

+

2

y

=

-

x

+

2

6

=

6

6

=

6

Since

6

=

6

6

=

6

, the equation will always be true.

y

=

−

x

+

2

y

=

-

x

+

2

Always true

Remove any equations from the system that are always true.

y

=

−

x

+

2

x=0 and y=2

Step-by-step explanation:

Just substitute y into the other equation. So, it would be 3x + 3 (x+2) = 6. Also, put parenthesis when substituting. :)

answer: 0+0=0

step-by-step explanation:

that is the only answer that can make 0