A rocket is launched from the top of an 60 foot cliff with an initial velocity of 150 ft./s. The height H of the rocket after T seconds is given by the equation H = -16t2+150t+60. how long after the rocket is launched will it be 20 feet from the ground?

f(x) = y

f(-3) = -5

step-by-step explanation:

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!

it shoild be o

step-by-step explanation:

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