The local regional transit authority of a large city was interested in determining the mean commuting time for workers who drove to work. They selected a random sample of 125 residents of the metropolitan region and asked them how long they spent commuting to work (in minutes). A 95% confidence interval was constructed and reported as (27.74, 30.06). Interpret the interval in the context of this problem. 2. A long distance telephone company recently conducted research into the length of calls (in minutes) made by customers. In a random sample of 45 calls, the sample mean was minutes and the standard deviation was s 5. 2 minutes. (a) Find a 95% confidence interval for the true mean length of long distance telephone calls made by customers of this company. x 1 . 68

yess

step-by-step explanation:

idk whyy this is happening, i cant even read my notification bc i keep getting errors

~coco

the answer is mp

step-by-step explanation:

first 15 divide by 2 = 7.5

100 divided by 7.5 is 13.

15 / 2 = 7.5

100 / 7.5 = 13.

d: (13,-1)

step-by-step explanation:

we know the starting point is (1,5)

the ending point is (x,y)   (cristians house)

the total distance is 6 units (5: 1)  

the fast food restaurant is at (11,0) and is 5/6ths of the way from the starting point to the ending point

ending minus starting point * 5/6   is how far they went

(x-1) *5/6, (y-5) * 5/6

we then need to add the starting point to determine the location

5/6(x-1) + 1, (y-5) * 5/6 + 5

this equals the fast food location of 11,0

setting the x locations equal

5/6 (x-1) +1 =11

subtracting 1 from each side

5/6 (x-1) +1-1 =11-1

5/6(x-1) =10

multiplying by 6/5 on each side

6/5*5/6(x-1) = 10*6/5

x-1 =12

add 1 to each side

x-1+1 =12+1

x=13

do the same for the y coordinate

(y-5) * 5/6 + 5 =0

subtract 5 from each side

(y-5) * 5/6 + 5-5 =0-5

5/6 (y-5) = -5

multiplying by 6/5 on each side

6/5*5/6 (y-5) = -5 *6/5

y-5 = -6

add 5 to each side

y-5+5 = -6+5

y=-1

the ending point , or the coordinates of cristians house is

(13,-1)