Write \displaystyle y = −x^2 + 12x − 5y=−x2+12x−5 into the form \displaystyle y = a(x − h)^2 + k. y=a(x−h)2+k. GIVEN that h =h=\frac{-b}{2a}2a−b​ and k=k= \fra c{4ac-b^{2}}{4a}4a4ac−b2​

then hh= kk=

FINALLY yy= (x-x− )^{2}2++

Write \displaystyle y = −x^2 + 12x − 5y=−x2+12x−5 into the form \displaystyle y = a(x − h)^2 + k. y=a(x−h)2+k.

GIVEN that h =h=\frac{-b}{2a}2a−b​ and k=k= \fra c{4ac-b^{2}}{4a}4a4ac−b2​

then hh= kk=

FINALLY yy= (x-x− )^{2}2++​