What are the vertices of angle A’B’C’ if angle ABC is dilated by a scale factor of 2?

irst, find the z score of a score of 80. this is given by the formula z = (x-u)/o, where x is the score, u is the mean, and o is the standard deviation. this gives

z = (80-78)/12 = 1/6 = .1667

now, find what percentile a z score of 1/6 correlates to in the normal distribution.

a z score of 1/6 = .1667 is equivalent to the 56.36th percentile of the distribution. so the probability a score is over this is 1-.5636 = .4364

the mean of a sample mean is equal to the original mean. however, the standard deviation of a sample mean is equal to the original standard deviation divided by the square root of n (sample size). so the new standard deviation is 12/sqrt(16) = 3.

the new z score is 80-78/3 = 2/3 = .667. this is equivalent to the 74.86th percentile. so the probability that the mean will be greater than this score is 1-.7486 = .2514.

simplified/solved

anwser:

-80x^2+158x+158

i   want to say the correct answer is 12,000 correct me if i'm wrong

the area of the piece of paper =   27- inch square.

so, the length of the square piece of paper = = .

the side of the triangle cut = =

also the side of the small square cut =

so, the area of each triangle cut = 1/2 * .

so, the area of 4 triangles cut =

area of a small square cut =

total area of 4 triangles cut and a small square cut = 6+3 = 9 square inches.

reaming area of the octagonal window   = 27 - 9 = 18 square inches.