A classic physics problem states that if a projectile is shot vertically up into the
air with an initial velocity of 162 feet
per second from an initial height of 117
feet off the ground, then the height of
the projectile, h, in feet, t seconds after
it's shot is given by the equation:
h = – 16t2 + 162t + 117
Find the two points in time when the
object is 160 feet above the ground.
Round your answers to the nearest
hundredth of a second (two decimal
places)