Ineed undertanding this question.
h(x) = x2 + 1 k(x) = x – 2

evaluate 3h(2) + 2k(3) =

H(2) = 2^2 + 1 = 5
3h(2) = 3 (5) = 15

k(3) = x= 3 – 2 = 1
2k(3) = 2(1) = 2

so
3h(2) + 2k(3) = 15 + 1 = 16

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