Astatement sn about the positive integers is given. write statements sk and sk+1, simplifying sk+1 completely. show your work. sn: 1 ∙ 2 + 2 ∙ 3 + 3 ∙ 4 + . . + n(n + 1) = [n(n + 1)(n + 2)]/3

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).

unless if u could do my questions, if not i wouldn't want to