He coordinates of the vertices of △def are d(2, −1) , e(7, −1) , and f(2, −3) .

the coordinates of the vertices of △d′e′f′ are d′(0, −1) , e′(−5, −1) , and f′(0, −3) .

what is the sequence of transformations that maps △def to △d′e′f′ ?

Given that the coordinates of the vertices of △DEF are D(2, −1) , E(7, −1) , and F(2, −3) and the coordinates of the vertices of △D′E′F′ are D′(0, −1) , E′(−5, −1) , and F′(0, −3) .

Notice that the y-coordinates of the pre-image and that of the image are the same, which means that there is a reflection across the y-axis.

A refrection across the y-axis results in the change in sign of the x-coordinates of the pre-image and the image while the y-coordinate of the image remains the same as that of the pre-image.

A refrection across the y-axis of △DEF with vertices D(2, −1) , E(7, −1) , and F(2, −3) will result in and image with vertices (-2, -1), (-7, -1) and (-2, -3) respectively.

Notice that the x-coordinate of the final image △D′E′F′ with vertices D′(0, −1) , E′(−5, −1) , and F′(0, −3) is 2 units greater than the vertices of the result of recting the pre-image across the y-axis.

This means that the result of refrecting the pre-image was shifted two places to the right.

Therefore, the sequence of transformations that maps △DEF to △D′E′F′ are reflection across the y-axis and translation 2 units right.

The answer would be d i think but i’m for sure it is not a and c

The answer is idk yo