What is the equation of the graphed line in point-slope form?
y + 6 = 3/4 (x + 4)
y + 4 = 3/4 (x + 6)
y + 6 = -3/4 (x + 4)
y + 4 = -3/4(x + 6)

The equation of a line that passes through the point (x1,y1) and has a slope of m is
y-y1=m(x-x1)

so
we see that the slope is rise/run=3/4
3 points we see are (-4,-6), (0,-3) and (4,0)

we get the equations

y+6=3/4(x+4)
y+3=3/4(x+0)
y+0=3/4(x+4)

answer is the first equaiton
y+6=3/4(x+4)

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