Mathematics, 20.12.2019 18:31 novarosell
Arectangle with an area of 240 in2 has a length 10 inches shorter than five times its width. which equation could be used to solve for the length of the rectangle?
a) 5w2 + 10w + 240 = 0
b) 5w2 − 10w + 240 = 0
c) 5w2 + 10w − 240 = 0
d) 5w2 − 10w − 240 = 0
Answers: 2
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Arectangle with an area of 240 in2 has a length 10 inches shorter than five times its width. which e...
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