If a mixture of a 6% acid solution with an 11% acid solution is to be made, how much of each solution is needed to make 10 liters of an 8% acid solution

X - 6%
y - 11%
We need 10 liters of 8%.
A) x + y = 10
B) .06x + .11y = (10 * .08)
Multiplying equation A by -.06
A) -.06x + -.06y = -.6   Then adding this to B)
B) .06x + .11y = (10 * .08)
.05y = .2
y = 4 liters of 6%
x = 6 liters of 11%