Avolleyball team had 6 boys and 5 girls on it. the team needed 2 equipment managers. the coach selected 1 player at random to be an equipment manager and then selected 1 of the remaining players at random to be the other equipment manager.
what is the probability that both equipment managers were girls? express your answer in simplest form.
i am so confused

Ok, so first of all there are 11 players to start off with. So, the first time the coach selects a player, there is a 5/11 chance, that there will be a girl picked. After this, the number on the bottom goes down to 10. Assuming there was a girl picked, the top number is now a 4, because there is now one less girl to be chosen. So now, you multiply the first number by the second number. This is because the first condition has to happen for the second condition to occur. I hope that explains everything.

put like terms together.orremember that the 45 becomes negative when moved to the other side.orthe minuses cancel out.