Mathematics, 06.01.2020 14:31 jadalove45

Billy's plant grows at least 2 inches a month.

graph the solution to the scenario by dragging and dropping a circle/arrow onto the number line.

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Answer from: kingoftime

y=2x+k

Step-by-step explanation:

y=2x+k

Here we are given that the plant growth is fixed by 2 inches for every month.

hence ,

if we assume that the plant had zero height at beginning , when the time was also zero, then in the next month that is 1st month the height of the plant will be 2 inches, similarly in the 2nd month the height will be 4 inches , for the third month the height of the plant will be 6 inches and so on.

So, if we plot them on a graph , taking time in month on x axis and height of the plant on y axis , the pattern of growth as mentioned above will give us few coordinates like,

(0,0) , (1,2) , (2,4) , (3,6) and so on..

hence from here we can determine equation which refers the above situation by using two point form of an equation . The two point form is given as

$\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}$

where

(x_1,y_1) and (x_2,y_2) are (1,2) and (2,4) respectively

substituting them in the above formula we get

$\frac{y-2}{x-1}=\frac{4-2}{2-1}$

$\frac{y-2}{x-1}=2$

y-2=2(x-1)

y-2=2x-2

y=2x

Hence we get out scenario , in equation as y=2x

Note:

this is the situation when the height of the plant was considered 0 at time 0 . however , if the initial height of the plant was k ( assumption )

The equation would have been like this

y=2x+k

This is because in both the cases the slope of the line would be same , as slope represents the rate of increase of y with respect to x . in this case it would be the increased in the height of the plant with respect to the months Where k represent the value of y at x= 0 , or the height of the plant at time 0 month.

Please refer to the image attached with this.

Billy's plant grows at least 2 inches a month. graph the solution to the scenario by dragging and dr

Answer from: Quest

answer: 2/4

step-by-step explanation:

Answer from: Quest

$w\geq 14$

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

$2l+2w\geq 40$

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

$2\times 6+2w\geq 40$

now, we can solve for w

$12+2w\geq 40$

subtract both sides by 12

$12+2w-12\geq 40-12$

$2w\geq 28$

divide both sides by 2

and we get

$w\geq 14$

so,

the smallest possible measurement of the width is 14 feet

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Billy's plant grows at least 2 inches a month.

graph the solution to the scenario by dra...