Aball is thrown into the air with an upward velocity of 36 ft/s. its height h in feet after t seconds is given by the function h = −16t2 + 36t + 9. in how many seconds does the ball reach its maximum height? round to the nearest hundredth if necessary. what is the ball’s maximum height?

a. 1.13 s; 69.75 ft

b.1.13 s; 29.25 ft

c.2.25 s; 9 ft

d.1.13 s; 31.5 ft

 B) 1.13 s; 29.25 ft

Step-by-step explanation:

Height of the ball h in feet after t seconds is given by the function

Now at maximum height

=>

After rounding to nearest hundredth,

Height ,

Therefore , t=1.13 s and  

Thus correct option is B) 1.13 s; 29.25 ft

you didn't post any answer choices, so its not 100% clear what your teacher is looking for

however, log(15/7) is equivalent to log(15) - log(7)

i'm using the rule log(x/y) = log(x) - log(y)