A37-inch piece of steel is cut into three pieces so that the second piece is twice as long as the first piece, and the third piece is two inches more than four times the length of the first piece. find the lengths of the pieces.

1st piece = x

 2nd piece = 2x

 3rd piece = 4x+2

x + 2x +4x +2 = 37

7x+2 =37

7x = 35

x = 35/7 = 5

 1st piece = 5 inches

 2nd piece = 10 inches

3rd piece = 22 inches

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!