The sum of 4 consecutive integers is 222. find the integers

The integers are 54, 55, 56 and 57

Let the integers be n, n + 1, n + 2 and n + 3.

Since the sum of the integers equals 222, we have that

n + n + 1 + n + 2 + n + 3 = 222

Collecting like terms, we have

n + n + n + n + 1 + 2 + 3 = 222

Simplifying, we have

4n + 6 = 222

Subtracting 6 from both sides, we have

4n + 6 - 6 = 222 - 6

4n = 216

Dividing both sides by 4, we have

n = 216/4

n = 54

Since n = 54, the first integers is 54

The second integer is n + 1 = 54 + 1 = 55,

The third integer is n + 2 = 54 + 2 = 56 and

The fourth integer is n + 3 = 54 + 3 = 57

So, the integers are 54, 55, 56 and 57

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222/4 = 55.5

take the 2 whole numbers below and above that

54 +55 +56 +57 = 222

jml angle lkj & angle mj = lm

unless you made a typo, the answers are both a and c.

step-by-step explanation:

1.5/3 is .5 whereas 3/9 is .3333333 not proportional

22/33 is .66666 and 4/6 is also .66666 proportional

2/4 is .5 whereas 142/213 is .66666 not proportional

14/7 is 2 and 7/3.5 is also 2 proportional

you could've also checked it by doing this simple division:

if the larger fraction divides with the smaller fraction to equal 1, it is proportional. so let me show you what i mean:

when i divide 22/33 by 4/6 i get 1, so we know it is proportional, and it is the same with 14/7 and 7/3.5. now if i divide 3/9 by 1.5/3 i get .66666 so therefore we know it is not proportional.

there are many ways to do this so i wanted to show you some possible ways.