Consider the quadratic equation. x^2=4x-5. how many solutions does the equation have?
a.) one real solution
b.) two real solutions c.)no real solutions
d.)cannot be determined

x^2=4x-5
subtract 4x from both sides
x^2-4x=-5
add 5 to both sides
x^2-4x+5=0

input into quadratic formula which is x= or

si ax^2+bx+c
so a=1
b=-4
c=5
input
=== representeds by 'i' so solution is 3i

then if other way around then wyou would do
= and [\tex]\sqrt{-1} [/tex] is represented by i

the solution is x=3i or i (i=)
but i is not real, it is imaginary so there are no real solution so the answer is C