F(x)=x-6 and g(x)= x^1/2 (x+3) find g(x) x f(x)

G(x) = x^(1/2) (x + 3) )

Apply distributive property:

 x^(1/2 + 1)  + 3 x^(1/2) = x^(3/2) + 3x^(1/2)

Multiply the two functions:

[x^(3/2) + 3x^(1/2)] * [x - 6] = x^(3/2 + 1) - 6x^(3/2) + 3x^(1/2 + 3/2) - 18x^(1/2)

= x^(5/2) - 6x^(3/2) + 3x^2 - 18x^(1/2)

Order:

x^ (5/2) + 3x^2 - 6x^(3/2) - 18x^(1/2) < answer

The answer of the above question is