Simplify using the horizontal method (2n^2+5n+5)(2n-4)

( 2n² + 5n + 5 ) ( 2n - 4 ) = 4n³ + 2n² -10n -20

Step-by-step explanation:

Given Expressions for Product: ( 2n² + 5n + 5 ) ( 2n - 4 )

To find: Product of the expression.

Consider,

( 2n² + 5n + 5 ) ( 2n - 4 )

⇒ 2n² ( 2n - 4 ) + 5n ( 2n - 4 ) + 5 ( 2n - 4 )

⇒ 2n² × 2n + 2n² × (-4) + 5n × 2n + 5n × (-4) + 5 × 2n + 5 × (-4)

⇒ 2 × 2 × n² × n + 2 × (-4) n² + 5 × 2 × n × n + 5 × (-4) n + 10n + (-20)

⇒ 4n³ + (-8)n² + 10n² + (-20)n + 10n -20

⇒ 4n³ - 8n² + 10n² - 20n + 10n -20

⇒ 4n³ +( -8 + 10 ) n² + ( -20 + 10 ) n -20

⇒ 4n³ + 2n² -10n -20

Therefore, ( 2n² + 5n + 5 ) ( 2n - 4 ) = 4n³ + 2n² -10n -20

answer: none of these answers are correct only the second half is

step-by-step explanation:

current in the circuit at time t is /, then the power delivered to the resistor is

step-by-step explanation: