Find the distance traveled in 15 seconds by an object moving with a velocity of v(t)=20 + 7cost feet per second

The distance traveled by the object at the given time  is 401.4 ft

The given parameter:

time of motion, t = 15 s

velocity of the object, v(t) = 20 + 7 cos(t) ft/s

To find:

The velocity of the object at the given time is calculated as:

The distance moved by an object is given by the following kinematic equation:

Thus, the distance moved by the object is 401.4 ft

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401.421 feet

Step-by-step explanation:

Given :

To Find : Find the distance traveled in 15 seconds by an object

Solution:

Equation :

where v is the speed and t is the time

Substitute t = 15

So, Speed = 26.7614 feet / second

Time = 15 seconds

Distance =

Distance =

Distance = 401.421 feet

Hence the distance traveled in 15 seconds by an object moving with a velocity of feet per second is 401.421 feet

the least common denominator is 40