Given the arithmetic sequence an= 2 - 5(n +1), what is the domain for n?

We are given the equation:

an= 2 - 5(n +1)                                   ---> eqtn 1

The domain is defined to be all the values of the input variable (in this case n) in which the function is defined. Or in other words, all the values of n in which we can have reasonable value of an.

But before we find for the domain, let us first define the variables. A standard arithmetic sequence or series has a general form of:

an = a1 + d (n – 1)                            ---> eqtn 2

where,

an = is the nth value specified by the value of n

a1 = is the 1st value or 1st term

d = is the common difference

n = the order of value

We can see from equation 2 that our a1 corresponds to an n value of n = 1 so that the factor d (n – 1) is cancelled leaving us with a1 alone. So the domain starts from 1 to positive infinity or in other words, all positive integers.

However in our equation 1, this is not the case, we can only get a1 when n = -1, therefore our domain starts from -1. So the domain is:

-1 , 0 and all positive integers

(n ≥ -1)

the answer is b.

step-by-step explanation:

by the trigonometric ratio tangent, tangent equals opposite divided by adjacent.

therefore, tan(50) equals ac/3

multiply each side by 3 to get: ac=3tan(50)

the answer is b.

the answer is:

the correct option:

b.

to solve the problem, we need to remember how to operate to simplify exponential expressions using the logarithms.

we are given the equation:

then, using placing logarith with base 7 on both sides of the equation, we have:

so, rounding the obtained result to two decimal places (nearest hundreth), we have:

hence, we have that the correct option:

b.

have a nice day!