Aball is thrown from a height of 40 meters with an initial downward velocity of 10/ms . the ball's height h (in meters) after t seconds is given by the following. =h−40−10t5t2 how long after the ball is thrown does it hit the ground?

After 2 seconds the ball will hit the ground.

Step-by-step explanation:

A ball is thrown from a height of 40 meters with an initial downward velocity of 10/ms .

The ball's height h (in meters) after t seconds is given by the function

At ground level height of ball is 0.

Splitting the middle term.

Using zero product property we get

The time can not be negative. So, the value of t is 2

Therefore after 2 seconds the ball will hit the ground.

a

step-by-step explanation:

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.