The function h(t) = −16t2 + 64t + 12 shows the height h(t), in feet, of a baseball after t seconds. a second baseball moves in the air along a path represented by g(t) = 10 + 10.4t, where g(t) is the height, in feet, of the object from the ground at time t seconds.
part a: create a table using integers 1 through 4 for the 2 functions. between what 2 seconds is the solution to h(t) = g(t) located? how do you know? (6 points)
part b: explain what the solution from part a means in the context of the problem. (4 points)

Two functions are:

H(t) = -16t² + 64t + 12

g(t) = 10 + 10.4t

Part A:

to find: table showing value of h(t) and g(t) for t = 1 , 2 , 3 , 4

Table is attached.

The solution to H(t) = g(t) is located between 3 and 4 seconds. because between 3 & 4 value of H(t) goes from 60 to 12 and value g(t) goes from 41.2 to 51.6   only in these intervals we can get equal values of H(t) and g(t).

Part B:

Solution for t,

H(t) = g(t)

- 16t² + 64t + 12 = 10 + 10.4t

- 16t² + 53.6t + 2 = 0

We find value of t using quadratic formula,

we get,

t = 3.39 seconds other value is neglected because of negative value.

This shows that at time 3.39 seconds both balls are at same height.

im not quite sure if this is right but i got 5.6 oisutuve

step-by-step explanation: