H(t)=15-10t-16t^2 if a snowboarders horizontal velocity is 10feet per second, how far from the base of the overhang will she land? 15 equals initial height of overhang, -10 is the initial vertical velocity and t is the time.

H ( t ) = 15 - 10 t - 16 t² = - 16 t² - 10 t + 15
15 ft is the initial height, or H ( 0 ) and - 10 ft / s  is the initial vertical velocity and 10ft/s is horizontal velocity. As for the time:
t 1/2 = (- b +/- √( b² - 4 a c ) )/ 2 a
t 1/2 = ( 10+/-√(100 + 960 ) ) / ( -32 ) =
= ( 10 - 32.56 ) / ( -32 ) = - 22.56 / ( - 32 ) = 0.705 s  ( another solution is negative )
d = vo x · t = 10 ft/s · 0.705 s = 7.05 ft.
She will land 7.05 ft from the base of the overhang. 

The answer would be $68.04

Thats where they was ported and the fields that noone really knew much about needed tended, so they put slaves out there do free work and huge profits and so on the north decided to hold its own and was more different way of survival did not have same climate conditions to afford protecting slaves from winter so expenses be diff from south