Consider the quadratic function f(x) = 2x2 – 8x – 10. the x-component of the vertex is . the y-component of the vertex is . the discriminant is b2 – 4ac = (–8)2 – (4)(2)(–10) =

F(x) = 2x² - 8x - 10.
This is a parabola open upward (since a>0) with an axis of symmetry = -b/2a:
a) axis of symmetry: x = -(-8)/(2*2) = 8/4 = 2. Then x = 2, which is the x component of the vertex
b) for x =  2, f(x) = f(2) = - 18 (component of y of the vertex)
c) VERTEX(2, - 18)
d) DISCRIMINENT: b² - 4.a.c = 64 - 4*2*(-10) = 144

The answer would be a