Circle a and circle b are congruent. cd is a chord of both circles. if ab = 8 ft and cd = 6 ft, how long is a radius?

Let us say that the intersection point of lines AB and CD is called point E. The lines AB and CD are perpendicular to each other which also means that the triangle CEB is a right triangle.

Where the line CB is the radius of the circle while the side lengths are half of the whole line segment:

EB = 0.5 AB = 0.5 (8 ft) = 4 ft

CE = 0.5 CD = 0.5 (6 ft) = 3 ft

Now using the hypotenuse formula since the triangle is right triangle, we can find for the radius or line CB:

CB^2 = EB^2 + CE^2

CB^2 = (4 ft)^2 + (3 ft)^2

CB^2 = 16 ft^2 + 9 ft^2

CB^2 = 25 ft^2

CB = 5 ft = radius

i think the answer is b.

step-by-step explanation:

not 100% sure though.

answer4 to the second power is 16

and 4 to the third power is 64,