equation 1: m = 8 + 2n
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Mathematics, 29.01.2020 09:43 solphiafischer
The work of a student to solve a set of equations is shown:
equation 1: m = 8 + 2n
equation 2: 4m = 4 + 4n
step 1: β4(m) = β4(8 + 2n) [equation 1 is multiplied by β4.]
4m = 4 + 4n [equation 2]
step 2: β4m = β32 β 8n [equation 1 in step 1 is simplified.]
4m = 4 + 4n [equation 2]
step 3: β4m + 4m = β32 β 8n + 4n [equations in step 2 are added.]
step 4: 0 = β32 β 4n
step 5: n = β8
in which step did the student first make an error?
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Answers: 3
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The work of a student to solve a set of equations is shown:
equation 1: m = 8 + 2n
equation 1: m = 8 + 2n
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